Lim x tends to infinity [(x+1) 10 +(x+2) 10 +..........(x+100) 10 ]÷[x 10 +10 10 ]

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Deepak Kumar Shringi · Answer

just divide bothnumerator and denominator by x^10 so all other terms other than x^10 will become zero answer will be coff of x^10 innumerator by denominator that is 100

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Lim x tends to infinity [(x+1) 10 +(x+2) 10 +..........(x+100) 10 ]÷[x 10 +10 10 ]

Lim _{x tends to infinity}[(x+1)¹⁰+(x+2)¹⁰+..........(x+100)¹⁰]÷[x¹⁰+10¹⁰]

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Lim x tends to infinity [(x+1) 10 +(x+2) 10 +..........(x+100) 10 ]÷[x 10 +10 10 ]

Lim x tends to infinity[(x+1)10+(x+2)10+..........(x+100)10]÷[x10+1010]

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Lim _{x tends to infinity}[(x+1)¹⁰+(x+2)¹⁰+..........(x+100)¹⁰]÷[x¹⁰+10¹⁰]