badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

lim x tending to 0 (((cos x)^(1/2) - (cos x)^(1/3)) / (sin x)^2).Please solve this.

2 years ago

Answers : (4)

Nandana
110 Points
							
hi !
Ans : -1/6
     Limx--> 0 √cosx – (cosx)1/3     0  form [LHospital’s rule]
                         sin2 x              0
        
       Limx--> 0  [ ½  (√cosx)½ – 1/3 (cosx)-2/3 ] sinx   = [ -½  (√cosx)-1 +1/3 (cosx)-2/3 ]
                                        2 sin x cosx                                            2cosx
                                                                                  =  -1/2 +1/3 = -1/6
2 years ago
Debayan das
18 Points
							The answer of this question is -1/12.Your  answer  is  not  correct  .The answer of this question is -1/12.Your  answer  is  not  correct  .
						
2 years ago
Nandana
110 Points
							hi !Sorry in my last answer I did a small mistake !Ans : -1/6     Limx--> 0 √cosx – (cosx)1/3     0  form [LHospital’s rule]                         sin2 x              0               Limx--> 0  [ ½  (√cosx)½ – 1/3 (cosx)-2/3 ] sinx   = [ -½  (√cosx)-1 +1/3 (cosx)-2/3 ]                                        2 sin x cosx                                            2cosx   Here is my mistake   ,                                                                       = 1/2 (-1/2 +1/3) = -1/12    Now ok no ?It `s a calculation mistake , sorry & thank you very much for telling !
						
2 years ago
Nandana
110 Points
							
hi ,
  sorry for my mistake !
 actually, what I did is correct but in the last step I did forget to multiply by half 
here is what I ‘m talking about
 
      
   Limx--> 0 √cosx – (cosx)1/3     0  form [LHospital’s rule]
                           sin2 x              0
   
  Limx--> 0  [ ½  (√cosx)½ – 1/3 (cosx)-2/3 ] sinx   = Limx--> 0 [ -½  (√cosx)-1 +1/3 (cosx)-2/3 ]
                                        2 sin x cosx                                                   2cosx
                                                                             =  ½ (1/3 -1/2) = -1/12
                                as your Answer !
    
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details