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lim x+sinx = x-sinxx-> infinity Please give the a answer.
we know that lim sinx/x as x tends to infinity is zero (by sandwich theorem)now, let f(x)=sinx/xso, the above lim can be rewritten as lim (1+f(x))/(1 – f(x)) as x tends to infinitywhich becomes (1 – 0)/(1+0)so, the value of the limit is 1.
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