Lim. x (e 2+x -e 2 )/1-cosx x=> 0

Lim. x (e2+x-e2)/1-cosx
x=> 0


2 Answers

Sher Mohammad IIT Delhi
askIITians Faculty 174 Points
8 years ago
Lim. x (e2+x-e2)/1-cosx
x=> 0
it is a 0/0 form,

so differentiate above and below,
Lim. (x (e2+x)+ (e2+x-e2))/sinx
x=> 0

again differentiate,

Lim. (x (e2+x)+e2+x+ (e2+x))/cosx
x=> 0


Arun Kumar IIT Delhi
askIITians Faculty 256 Points
8 years ago

because it approaches from the negative side.
So the limit diverges

Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

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