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Grade: 11
        
Lim. x (e2+x-e2)/1-cosx
x=> 0
3 years ago

Answers : (2)

Sher Mohammad
IIT Delhi
askIITians Faculty
174 Points
							
Lim. x (e2+x-e2)/1-cosx
x=> 0
it is a 0/0 form,

so differentiate above and below,
Lim. (x (e2+x)+ (e2+x-e2))/sinx
x=> 0

again differentiate,

Lim. (x (e2+x)+e2+x+ (e2+x))/cosx
x=> 0

(1+1)/1=2



3 years ago
Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							Hi


because it approaches from the negative side.
So the limit diverges

Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

3 years ago
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