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Lim √(x^2+1) -1/√(x^2+9)-3 x--->0 Please provide me with the answer.

Lim √(x^2+1) -1/√(x^2+9)-3
x--->0
Please provide me with the answer. 

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1 Answers

Aditya Gupta
2081 Points
3 years ago
we can write √(x^2+1) -1 as (√(x^2+1) – 1)(√(x^2+1) + 1)/(√(x^2+1) + 1)= x^2/(√(x^2+1) + 1)
similarly write √(x^2+9)-3 as (√(x^2+9) – 3)(√(x^2+9) + 3)/(√(x^2+9) + 3)= x^2/(√(x^2+9) + 3)
so that √(x^2+1) -1/√(x^2+9)-3= (√(x^2+9) + 3)/(√(x^2+1) + 1)
now taking limit x tends to 0,
6/2
= 3
kindly approve :)

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