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`        Lim √(x^2+1) -1/√(x^2+9)-3x--->0Please provide me with the answer. `
9 months ago

```							we can write √(x^2+1) -1 as (√(x^2+1) – 1)(√(x^2+1) + 1)/(√(x^2+1) + 1)= x^2/(√(x^2+1) + 1)similarly write √(x^2+9)-3 as (√(x^2+9) – 3)(√(x^2+9) + 3)/(√(x^2+9) + 3)= x^2/(√(x^2+9) + 3)so that √(x^2+1) -1/√(x^2+9)-3= (√(x^2+9) + 3)/(√(x^2+1) + 1)now taking limit x tends to 0,6/2= 3kindly approve :)
```
9 months ago
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