Lim x->0(xcosx-log(1+x))/x^2.Limx->0 (xcosx - x )/x^2 (by elimination )Lim x->0 (cosx - x)/xWhich is finally equal to zero but by using expansion and L hospital`s rule i get the answer 1/2.What is wrong in this method ?

shashwat , 9 Years ago

Grade 12