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lim x- 0 {(sin2x 2sin^2x-2sinxcosx-cos^2x}Solve by differentiation
You can do it by using lim x----> 0 sinx/x=1.Just solve as per this guideline.After putting limit you will get 2x.2x²- 2x-1= 4x³-2x-1. We can`t do it by differentiation as for L Hospital We should have a function in form of 0/0 or infinity/infinity.So use this one.So at all your ans will be -1
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