Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
lim (sin2x)tan^2(2x)x_pie/4
1infiniteformlim x_pie/4 (1+sin2x-1)^tan^2(2x)=e^(lim x_pie/4 (sin2x-1)*(tan^2(2x)))apply L Hospital rule because 0/0 forme^(lim x_pie/4 (sin2x-1)/(cot^2(2x))=e^(lim x_pie/4 (2*cos2x)/(4*cot2x*cosec^2(2x))=e^(lim x_pie/4 (2*cos2x*sin^3(2x))/(4*cos2x)=e^(1/2)Sher Mohammadfaculty askiitians
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -