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Grade: 11
        
 
lim [n2-n+1/n2-n-1]n(n-1)
n_#
# is infinity
3 years ago

Answers : (1)

Sher Mohammad
IIT Delhi
askIITians Faculty
174 Points
							1^(infinite form)
lim n_infinite[n2-n+1/n2-n-1]^(n(n-1))

=lim n_infinite(1+2/n2-n-1)^n(n-1)
=e^(lim n_infinite 2n(n-1)/n2-n-1)
=e^(lim n_infinite 2-2/n)/1-1/n-1/n2)
=e^2

Sher Mohammad
Faculty askiitians

3 years ago
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