lim (asinx-xsina)/(ax^2-xa^2)
x tend to a.
lim (asinx-xsina)/(ax^2-xa^2)
x tend to a.
Mostafijur Rahaman , 11 Years ago
Grade 12
Differential Calculus> find...
3 Answers
bharat bajaj
Last Activity: 11 Years ago
This is 0/0 form equation. So, use L-Hospital Rule, Differentiate both upper and lower sides wrt x.
lim ( a cosx - sina )/ (2ax - a^2)
Now lim x->a,
Therefore,
Ans = a cosa - sina/(a)^2
lim ( a cosx - sina )/ (2ax - a^2)
Now lim x->a,
Therefore,
Ans = a cosa - sina/(a)^2
Thanks & Regards
Bharat Bajaj
askIITians Faculty
IIT Delhi
Sunil Raikwar
Last Activity: 11 Years ago
Given expression is in the form of 0/0 as we put a in place of x.
So we apply L-Hospital rule. According to L-Hospital rule differentiate numerator & denominator with respect to x. We get
lim(x tend to a)(acosx-sina)/(2ax-a2)
acosa-sina/ a2
Thanks & Regards
Sunil Raikwar
askIITians faculty
Mostafijur Rahaman
Last Activity: 11 Years ago
other than L Hospital`s rule how can we do it??
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