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Let B = lim(x -> 2) [tan(pi.x)/x-2]
B=?
I’m not allowed to use L'Hopital.

Allexandre , 8 Years ago
Grade 10
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

First method by expansion:
 
B = lim(x -> 2) [tan(pi.x)/x-2]
expand tan to 1 degree term .i.e pi.x
B = lim(x -> 2) [(pi.x)/x-2]
Now apply L-pital
pi/1
 
Second method substitute x = 2 + h with h → 0
and then apply l-hosiptal
u will get again pi.

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