let α and β be the distinct roots of ax2+bx+c=0 then limx→α1−cos(ax2+bx+c)/(x−α)^2 is equal to?

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Vikas TU · Answer

Since α,β are the roots of ax 2 +bx+c=0 limx→α (1−cos(x−α)(x−β)) / (x−α) 2 ⇒limx=α 2sin2(x−α)(x−β)2a2(x−α)2(x−β)24×a2(x−α)2(x−β)24(x−α)2 ⇒limx=α {(2sin 2 (x−α)(x−β) / 2) / ( a 2 (x−α) 2 (x−β) 2 / 4) } × {a 2 (x−α) 2 (x−β) 2 / 4(x−α) 2 } ⇒2×a 2 (α−β) 2 / 4 ⇒a 2 (α−β) 2 /2

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let α and β be the distinct roots of ax2+bx+c=0 then limx→α1−cos(ax2+bx+c)/(x−α)^2 is equal to?

let α and β be the distinct roots of ax2+bx+c=0 then limx→α1−cos(ax2+bx+c)/(x−α)^2 is equal to?

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let α and β be the distinct roots of ax2+bx+c=0 then limx→α1−cos(ax2+bx+c)/(x−α)^2 is equal to?

let α and β be the distinct roots of ax2+bx+c=0 then limx→α1−cos(ax2+bx+c)/(x−α)^2 is equal to?

1 Answers

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Other Related Questions on Differential Calculus

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