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Kindly answer fast.......... y=|tanx|Then find dy/dx.

Kindly answer fast.......... y=|tanx|Then find dy/dx.

Grade:12

1 Answers

Arun
25750 Points
6 years ago
Here we have to give answer in breaks as[0,pi/2), y= tanx hence dy/dx= sec^2x(pi/2,pi], y= -tanx hence dy/dx= -sec^2x[pi,3pi/2), y= tanx hence dy/dx= sec^2x(3pi/2,2pi], y= -tanx hence dy/dx= -sec^2x

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