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Grade: upto college level
        Is the function f (x) = |x2 - x| differentiable at x = 2. If yes find it’s derivative.
6 years ago

Answers : (5)

Parvez ali
askIITians Faculty
47 Points
							
147-1346_140303-103742.jpg



Thanks & Regards
Parvez Ali
askIITians Faculty

6 years ago
ruchi yadav
askIITians Faculty
26 Points
							
Yes fuction will be differentiable at x =2. which can easily be seen by graph of the function.

First draw the graph of y = x2-x and then take mode.

Derivative will be = 2x-1
at x= 2
Derivative will be 4-1 = 3


Thank You
Ruchi
Askiitians Faculty
6 years ago
Sher Mohammad
IIT Delhi
askIITians Faculty
174 Points
							yes,

for x>1, f(x)=x^2-x
f'(x)=2x-1
f'(2)=3
Sher Mohammad
B.Tech, IIT Delhi.

6 years ago
Sher Mohammad
IIT Delhi
askIITians Faculty
174 Points
							
|x(x-1)|=x(x-1) if x(x-1)>0 x belongs to (-inf,0) or (1,inf )
|x(x-1)|=x(x-1) x belongs to (0,1 )

for x>1
f'(x)=2x-1
f'(2)=3

Sher Mohammad
B.Tech, IIT Delhi

6 years ago
Ajay Verma
askIITians Faculty
33 Points
							
f(x)= | x^2 - x |
at x=2 ( x^2 - x ) > 0

so we can take f(x) = x^2 - x

for differentiability
L.H.D = R.H.D

L.H. D = {f(a-h) - f(a)} / -h
= {f (2-h) - f(2)} / -h
= {(2-h)^2 - (2-h) - 2 } / -h
= 3

R.H.D = { f(2+h) - f(2)}/ h
= {(2+h)^2 - (2+h) - 2 } / h
= 3

so its differentiable
and derivative = 3



Thanks and Regards,
Ajay verma,
askIITians faculty,
IIT HYDERABAD
6 years ago
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