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Is log(x!) differentiable ? If yes then dlog(x!)/dx = ?

Anshuman Mohanty , 8 Years ago
Grade 12th pass
anser 1 Answers
Nandana

Last Activity: 8 Years ago

yes , it is …
    firstly , d/dx (x!) = Gamma (x+1) ;
       take   x!= u , then
         d/du (log(u)) = 1/u
        so , d/dx (log x!) = 1/x!* d/dx(x!)
                                   = Gamma (x+1) /x!
 
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