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If y=x^x, then sjos that y''-(y')/y-y/x=0. Please answer the question.

If y=x^x, then sjos that y''-(y')/y-y/x=0.
Please answer the question.
 

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Grade:12

1 Answers

Arun
25758 Points
3 years ago
Dear Sagar
 
Y = x^x
 
taking log
 
log y = x logx
 
(1/y)* y' = x/x + log x
 
y' = y(1 + log x)
 
Now
 
y'' = y ( 1/x) + (1+ log x) y'
 
Put these in the given equation and you will get the desired result.
 

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