if y=(x-1) log(x-1) – (x+1) log(x+1) prove that dy/dx=log(x-1/1+x)

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Rinkoo Gupta · Answer

dy/dx=(x-1)/(x-1)+log(x-1).1 -{(x+1)/(x+1)+log(x+1).1 =1+log(x-1)-1-log(x+1) =log((x-1)/(x+1)) Thanks & Regards Rinkoo Gupta AskIITians Faculty

Arun Kumar · Answer

Hi Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

Riya gupta · Answer

dy/dx=(x-1)log(x-1)-(x+1)log(x+1) After solving it using quotient rule I.e f(x).g(x)=f(x) d/dx g(x) + g(x) d/dx f(x) dy/dx=(1+log(x-1))-(1+log(x+1)) dy/dx=log(x-1)-log(x+1) Now using property {log a pq=log a p-log a q} Final answer=log(x-1/x+1)=RHS

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if y=(x-1) log(x-1) – (x+1) log(x+1) prove that dy/dx=log(x-1/1+x)

if y=(x-1) log(x-1) – (x+1) log(x+1) prove that dy/dx=log(x-1/1+x)

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