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`        If y=sin^-1(sina.sinx/1-cosa.sinx)Then y'(0) isA)1B)2sinaC)tanaD)sina`
10 months ago

## Answers : (2)

Arun
22364 Points
```							 Dear student when you differentiate this, you get an expression. now put x = 0 in this expression, you will get sin a hence y’(0) = sin a
```
10 months ago
1655 Points
```							write siny= sinasinx/(1 – cosasinx)now differentiating wrt xcosy*y’(x)= sina[cosx(1 – cosasinx) + sinxcosxcosa]/(1 – cosasinx)^2when x=0, y=0so 1*y’(0)= sina/(1 – 0)= sina
```
10 months ago
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### Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions