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If y=sin^-1(sina.sinx/1-cosa.sinx) Then y'(0) is A)1 B)2sina C)tana D)sina

If y=sin^-1(sina.sinx/1-cosa.sinx)
Then y'(0) is
A)1
B)2sina
C)tana
D)sina

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Grade:12

2 Answers

Arun
25750 Points
5 years ago
 
Dear student
 
when you differentiate this, you get an expression.
 
now put x = 0 in this expression, you will get sin a
 
hence y’(0) = sin a
Aditya Gupta
2081 Points
5 years ago
write siny= sinasinx/(1 – cosasinx)
now differentiating wrt x
cosy*y’(x)= sina[cosx(1 – cosasinx) + sinxcosxcosa]/(1 – cosasinx)^2
when x=0, y=0
so 1*y’(0)= sina/(1 – 0)= sina

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