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if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)

if  x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)

Grade:12

1 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
7 years ago
Hi

Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

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