if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)

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if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)

if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)

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if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)

if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Differential Calculus

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