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if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x) if x^y . y^x=1 prove that dy/dx= -y(y+x log y)/x(y log x + x)
HiThanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
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