Grade 11Algebra
If xlog y=log x then show that dy/dx= y[1-logxlogy]/x(log2x)
If xlog y=log x then show that dy/dx= y[1-logxlogy]/x(log2x)
1 Answer
Aditya Gupta
hey yamini
take log on both sides
log xlog y= log(log x)
logy*log x = log(log x)
differentiate both sides wrt x
(1/y)*(y’)*log x + logy*1/x= 1/xlog x
so, y’= dy/dx= y[1 – logxlogy]/x(log2x)
kindly approve :)
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