Nishant Vora
Last Activity: 8 Years ago
Simplify algebra by making subs X=x/a, Y=y/b and m=n/(n-1)
Xᵐ + Yᵐ = 1 … (i)
Xacotα + Yb = pcosecα … (ii)
Diff (i) wrt X : mXᵐ⁻¹ + mYᵐ⁻¹(dY/dX) = 0 ⟹ dY/dX = −(X/Y)ᵐ⁻¹
At pt of contact (X,Y) have grad (i) = grad (ii) so −acotα/b=−(X/Y)ᵐ⁻¹ … (iii)
Sub in (ii) for acotα : bXᵐ/Yᵐ⁻¹ + Yb = pcosecα ⟹ b(Xᵐ+Yᵐ) = pYᵐ⁻¹cosecα ⟹ Yᵐ⁻¹ = (b/p)sinα
Also using (iii), Xᵐ⁻¹ = (a/p)cosα
Sub in (i) for X,Y and adjust to get (acosα/p)^(m/(m-1)) + (bsinα/p)^(m/(m-1)) = 1
Setting m/(m-1)=n and multiply by pⁿ gives desired result