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`        if x= a(t+sint) ;y=a(1-cost) then y2 that is second order derivative can we take second order derivative first and then divide??`
one year ago

```							Dear student you can only find first order derivative that way. Here x =a(t+Sint) and y =a(1-cost)Differentiating both sides w r t.t,We getdx/dt =a(1+cost) and dt/dt =a(Sint)Since dy/dx =(a sint)/a(1+cost)dy/dx =2 sin(t/2) cos(t/2) /2cos^2 (t/2)dy/dx =tan(t/2)Again differentiating both sides we getd^2 y /dx^2 =sec^2 (t/2) × 1/2 × dt/dxd^2 y /d^2 x =1/2 [sec^2 (t/2) ×1/a(1+cost) ]d^2 y /dx^2 =1/2[sec^2 (t/2) /2a cos^2 (t/2) ]Hence d^2 y /dx^2 =1/4a sec^4 (t/2)
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one year ago
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