if x=a sin t – b cos t, y=a cos t+ b sin t , prove that d2y/dx2= -(x^2+y^2/y^3)

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Rinkoo Gupta · Answer

x=asint-bcost y=acost+bsint squaring and then adding both eqs., we get x 2 +y 2 =a 2 +b 2 Now diff. w. r. to x 2x+2y.dy/dx=0 dy/dx=-x/y diff .w.r.to x again d 2 y/dx 2 = -{(y.1-x.dy/dx)/y 2 } = -{(y+x 2 /y)/y 2 }=-(x 2 +y 2 )/y 3 Thanks & Regards Rinkoo Gupta askIITians Faculty

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if x=a sin t – b cos t, y=a cos t+ b sin t , prove that d2y/dx2= -(x^2+y^2/y^3)

if x=a sin t – b cos t, y=a cos t+ b sin t , prove that d2y/dx2= -(x^2+y^2/y^3)

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if x=a sin t – b cos t, y=a cos t+ b sin t , prove that d2y/dx2= -(x^2+y^2/y^3)

if x=a sin t – b cos t, y=a cos t+ b sin t , prove that d2y/dx2= -(x^2+y^2/y^3)

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