if x = a cos t , y = b sin t . Then find the value of d^3y/dx^3 = ?

Question

Khimraj · Answer

x = acost dx/dt = -asint d 2 x/dt 2 = - acost d 3 x/dt 3 = asint y = bsint dy/dt = bcost d 2 y/dt 2 = – bsint d 3 y/dt 3 = – bcost d 3 y/dx 3 = (d 3 y/dt 3 )/(d 3 x/dt 3 ) = asint/(-bcost) = -(a/b)tant Hope it clears. If you like answer then please approve it.

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if x = a cos t , y = b sin t . Then find the value of d^3y/dx^3 = ?

if x = a cos t , y = b sin t . Then find the value of d^3y/dx^3 = ?

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if x = a cos t , y = b sin t . Then find the value of d^3y/dx^3 = ?

if x = a cos t , y = b sin t . Then find the value of d^3y/dx^3 = ?

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