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If P= x 3 - 1/ x 3 and Q=x-1/x , x belongs from 0 to infinity , find the minimum value of P/Q 2

5 years ago

Answers : (6)

udit maniyar
46 Points
							
P = x- 1/x3 =(x-1/x)(x+1/x2 +1)
Q=x – 1/x 
 
 
P/Q  when simplified it comes in the form of (x-1/x)+3/(x-1/x) 
then we can apply A.M greater than or equal to G.M
we get the minimum value of p/q2 as 2(3)1/2
 
5 years ago
udit maniyar
46 Points
							
if you feel the answer is right then approve it
5 years ago
grenade
2061 Points
							
but i was getting answer 2
5 years ago
udit maniyar
46 Points
							
did u get this after simplification p/q2 =  (x –  1/x) + 3/(x – 1/x) 
 
5 years ago
grenade
2061 Points
							
askiitians faculty pl. help us 
5 years ago
Tulika Sureka
24 Points
							
2(3)1/2 is the correct
5 years ago
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