Grade Select GradeDifferential Calculus
If P=x3 - 1/x3 and Q=x-1/x , x belongs from 0 to infinity , find the minimum value of P/Q2
If P=x3 - 1/x3 and Q=x-1/x , x belongs from 0 to infinity , find the minimum value of P/Q2
6 Answers
udit maniyar
Approved Tutor Answer11 Years agoP = x3 - 1/x3 =(x-1/x)(x2 +1/x2 +1)
Q=x – 1/x
P/Q2 when simplified it comes in the form of (x-1/x)+3/(x-1/x)
then we can apply A.M greater than or equal to G.M
we get the minimum value of p/q2 as 2(3)1/2
udit maniyar
if you feel the answer is right then approve it
grenade
but i was getting answer 2
udit maniyar
did u get this after simplification p/q2 = (x – 1/x) + 3/(x – 1/x)
grenade
askiitians faculty pl. help us
Tulika Sureka
2(3)1/2 is the correct
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