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If P=x3 - 1/x3 and Q=x-1/x , x belongs from 0 to infinity , find the minimum value of P/Q2

Tulika Sureka , 9 Years ago
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udit maniyar

Last Activity: 9 Years ago

P = x3 - 1/x3 =(x-1/x)(x2 +1/x2 +1)
Q=x – 1/x 
 
 
P/Q2   when simplified it comes in the form of (x-1/x)+3/(x-1/x) 
then we can apply A.M greater than or equal to G.M
we get the minimum value of p/q2 as 2(3)1/2
 

udit maniyar

Last Activity: 9 Years ago

if you feel the answer is right then approve it

grenade

Last Activity: 9 Years ago

but i was getting answer 2

udit maniyar

Last Activity: 9 Years ago

did u get this after simplification p/q2 =  (x –  1/x) + 3/(x – 1/x) 
 

grenade

Last Activity: 9 Years ago

askiitians faculty pl. help us 

Tulika Sureka

Last Activity: 9 Years ago

2(3)1/2 is the correct

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