If lim x tending to 0 x^3 / (a+x) ^1/2 (bx - sin x) = 1, then what is the value of (a+b) where a0?

Question

If lim x tending to 0 x^3 / (a+x) ^1/2 (bx - sin x) = 1, then what is the value of (a+b) where a>0?

Vikas TU · Answer

Dear student lim x tending to 0 x^3 / (a+x) ^1/2 (bx - sin x) = 1 Put down x^3 below , and apply limit b = 1, a = 36 a+b = 37 Hope this helps Good Luc

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If lim x tending to 0 x^3 / (a+x) ^1/2 (bx - sin x) = 1, then what is the value of (a+b) where a>0?

If lim x tending to 0 x^3 / (a+x) ^1/2 (bx - sin x) = 1, then what is the value of (a+b) where a>0?

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If lim x tending to 0 x^3 / (a+x) ^1/2 (bx - sin x) = 1, then what is the value of (a+b) where a>0?

If lim x tending to 0 x^3 / (a+x) ^1/2 (bx - sin x) = 1, then what is the value of (a+b) where a>0?

1 Answers

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