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Grade 12th passDifferential Calculus

  1. if klog25 = 16 , then find the value of k(log25)2 = ?

Profile image of LAKHAN SHARMA
10 Years agoGrade 12th pass
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3 Answers

Profile image of Arif Hossain
10 Years ago
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Profile image of Shaily Priya
6 Years ago
log2{ k(log25)^2} = log2 a
log2 5 log2 klog25 = log2 a
log2 5 log2 16 = log2 a
4 log2 5 = log2 a
    a=625
P.S.=we have assumed k(log2 5)^2 = a and then applied log2 both sides
Profile image of Vikas TU
6 Years ago
Dear student 
First you want to find what log5 base 2 is, which it comes out to about 2.322.
Next you want to find out what k equals. So you want to put both sides to the 1/2.322 power.
16^(1/2.322) = 3.3, so k=3.3.
Lastly you can plug 3.3 in for k.
3.3^{ (log5 base 2)^2 }
=624.439.

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