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if klog 2 5 = 16 , then find the value of k (log 2 5) 2 = ?

  1. if   klog25  = 16  , then find the value of k(log25)2 = ?  

Grade:12th pass

3 Answers

Arif Hossain
askIITians Faculty 52 Points
6 years ago
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Shaily Priya
34 Points
2 years ago
log2{ k(log25)^2} = loga
log5 logklog2= loga
log5 log16 = loga
4 log5 = loga
    a=625
P.S.=we have assumed k(log5)^2 = a and then applied logboth sides
Vikas TU
14149 Points
2 years ago
Dear student 
First you want to find what log5 base 2 is, which it comes out to about 2.322.
Next you want to find out what k equals. So you want to put both sides to the 1/2.322 power.
16^(1/2.322) = 3.3, so k=3.3.
Lastly you can plug 3.3 in for k.
3.3^{ (log5 base 2)^2 }
=624.439.

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