If fvis continuous at x=0, where f(x)= [sin(a+x) - sin(a-x)] / [tan(a+x) - tan(a-x)] for x=0 , then f(0)=

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Arun · Answer

Dear Daya 2 cos a sin x (cos (a+x) * cos (a – x)) / sin (2x) 2 cos a sin x (cos (a+x) * cos (a – x)) / 2 sin x cos x now cos a (cos (a+x) * cos (a – x)) / cos x put the limit cos^3 a Regards Arun

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If fvis continuous at x=0, where f(x)= [sin(a+x) - sin(a-x)] / [tan(a+x) - tan(a-x)] for x=0 , then f(0)=

If fvis continuous at x=0, where
f(x)= [sin(a+x) - sin(a-x)] / [tan(a+x) - tan(a-x)]
for x=0 , then f(0)=

1 Answers

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If fvis continuous at x=0, where f(x)= [sin(a+x) - sin(a-x)] / [tan(a+x) - tan(a-x)] for x=0 , then f(0)=

If fvis continuous at x=0, wheref(x)= [sin(a+x) - sin(a-x)] / [tan(a+x) - tan(a-x)]for x=0 , then f(0)=

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If fvis continuous at x=0, where
f(x)= [sin(a+x) - sin(a-x)] / [tan(a+x) - tan(a-x)]
for x=0 , then f(0)=