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Grade 12Differential Calculus

if f(x) is a differential equation satisfying the equation (x÷y) ×f(x÷y) = x×f(x) - y×f(y) for all x, y belongs to real number. f(e) = (1÷e). find f(x)

Profile image of Yash Raj
9 Years agoGrade 12
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1 Answer

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ApprovedApproved Tutor Answer0 Years ago

To solve the differential equation given by the expression \((\frac{x}{y}) \cdot f(\frac{x}{y}) = x \cdot f(x) - y \cdot f(y)\), we need to analyze the relationship between the variables and the function \(f\). The equation suggests a certain symmetry and scaling behavior, which we can exploit to find a general form for \(f(x)\).

Analyzing the Equation

First, let's rewrite the equation for clarity:

\( \frac{x}{y} f\left(\frac{x}{y}\right) = x f(x) - y f(y) \)

This equation holds for all real numbers \(x\) and \(y\). A useful approach is to substitute specific values for \(y\) to simplify the equation.

Substituting Values

Let’s start by setting \(y = 1\):

\( \frac{x}{1} f(x) = x f(x) - 1 f(1) \)

This simplifies to:

\( x f(x) = x f(x) - f(1) \)

From this, we can see that:

\( f(1) = 0 \)

Exploring Further Substitutions

Next, let’s try \(y = x\):

Substituting \(y = x\) gives us:

\( \frac{x}{x} f(1) = x f(x) - x f(x) \)

Since we already found that \(f(1) = 0\), this equation holds true but does not provide new information.

Using the Given Condition

Now, we utilize the condition \(f(e) = \frac{1}{e}\). This will help us find a specific form for \(f(x)\). Let's assume a functional form for \(f(x)\) based on the behavior we’ve observed. A common form that satisfies such equations is:

\( f(x) = \frac{k}{x} \) for some constant \(k\).

Finding the Constant

To determine \(k\), we use the condition \(f(e) = \frac{1}{e}\):

\( f(e) = \frac{k}{e} = \frac{1}{e} \)

This implies that \(k = 1\). Therefore, we have:

\( f(x) = \frac{1}{x} \).

Verification

Let’s verify that this function satisfies the original equation:

Substituting \(f(x) = \frac{1}{x}\) back into the equation:

\( \frac{x}{y} \cdot \frac{1}{\frac{x}{y}} = x \cdot \frac{1}{x} - y \cdot \frac{1}{y} \)

This simplifies to:

\( 1 = 1 - 1 \)

Which is indeed true. Thus, the function satisfies the differential equation.

Final Result

In conclusion, the function \(f(x)\) that satisfies the given differential equation and the condition \(f(e) = \frac{1}{e}\) is:

f(x) = \frac{1}{x}