if f(x)=cos-1[1-(log x)2]/[1+(log x)2] then the value of f’(e)= - 1
- 1/e
- 2/e
- 2/e2
if f(x)=cos-1[1-(log x)2]/[1+(log x)2] then the value of f’(e)=
- 1
- 1/e
- 2/e
- 2/e2
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