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if f(x)={ax^2+2bx+c]/[Ax^2 +2Bx+C] has extrem points at x=1 and x=-1 such that f(1)=2, f(-1)=3 and f(0)=2.5 then find the value of the function f(x).


one year ago

							Dear student The question is saying that f(1)=3It means that on putting x = 1, we get 3 as remainderf(1)= a(1)^2 + b(1) +23 = a+b + 2a+b = 1 -----------------(1)Now,Second casef(4)=42a(4)^2 + b(4) + 2 = 4216a + 4b = 404a+b = 10 ------------------(2)Subtracting equation 1 from 2, we get3a= 9a=3Now,On putting the value of a in equation 1, we getb= - 2

7 months ago
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