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`         If f(x)=1/(1-x) and g(x)=f[f{f(x)}] then g(x) is discontinuous at`
5 years ago

```							g(x)=f[f{f(x)}]=f[f{1/(1-x)}]=f[1/{1-(1/(1-x)}]=f[(x-1)/x]=1/1-{(x-1)/x}=1/[(x-x+1)/x]=xg(x)=x, which is a straight line passing through origin with slope 1.so g(x) is continuous everywhere.Thanks & RegardsRinkoo GuptaAskIITians Faculty
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5 years ago
```							 But sir answer is given x=0 and there is no options for everywhere continuous
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5 years ago
```							you can  check th continuity of the function at x=0 lhl at x-0 = lim h->0 f(0-h)=lim h->0 (-h)=0RHL at x=0 =lim h->0 f(0+h)=lim h->0 f(h)=lim h->0 ( h)=0lhl=rhl so it is continous at x=0
```
5 years ago
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