if ax^2+2hxy+by^2=1 then prove thatd2y/dx2=h^2-ab/(hx+by)^3

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Arun · Answer

Dear student 2ax+ 2h y + 2hx dy/dx + 2 by dy/dx = 0 2a + 2h dy/dx + 2hx d 2 y /dx 2 + 2 h dy/dx + 2 b(dy/dx) 2 + 2by d 2 y /dx 2 = 0 now you justhave to simplify here

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if ax^2+2hxy+by^2=1 then prove thatd2y/dx2=h^2-ab/(hx+by)^3

if ax^2+2hxy+by^2=1 then prove thatd2y/dx2=h^2-ab/(hx+by)^3

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if ax^2+2hxy+by^2=1 then prove thatd2y/dx2=h^2-ab/(hx+by)^3

if ax^2+2hxy+by^2=1 then prove thatd2y/dx2=h^2-ab/(hx+by)^3

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