If af(cotx)+bf(cotx)=x then find f'(cotx) 1)1/a-b 2)sin^2x/a+b 3)sin^2x/a-b 4)sin*^2x/b-a

Question

Aditya Gupta · Answer

i think there is a slight error in your ques in sign of b. still, i will solve it assuming it is correct we see that f(cotx)= x/a+b now, differentiate both sides wrt x and use chain rule f’(cotx)*(-cosec^2x)= 1/a+b so f’(cotx)= – sin^2x/(a+b)

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If af(cotx)+bf(cotx)=x then find f'(cotx) 1)1/a-b 2)sin^2x/a+b 3)sin^2x/a-b 4)sin*^2x/b-a

If af(cotx)+bf(cotx)=x then find f'(cotx)
1)1/a-b
2)sin^2x/a+b
3)sin^2x/a-b
4)sin*^2x/b-a

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If af(cotx)+bf(cotx)=x then find f'(cotx) 1)1/a-b 2)sin^2x/a+b 3)sin^2x/a-b 4)sin*^2x/b-a

If af(cotx)+bf(cotx)=x then find f'(cotx) 1)1/a-b2)sin^2x/a+b3)sin^2x/a-b4)sin*^2x/b-a

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If af(cotx)+bf(cotx)=x then find f'(cotx)
1)1/a-b
2)sin^2x/a+b
3)sin^2x/a-b
4)sin*^2x/b-a