MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
 If a is not = b,but a^2 = 5a – 3, b^2 = 5b –3, then the equation having a/b and b/a as its roots is – 
(A) 3x^2 – 25x + 3 = 0 
(B) x^2 + 5x – 3 = 0 
(C) x^2 – 5x + 3 = 0
 (D) 3x^2 – 19x + 3 = 0
20 days ago

Answers : (1)

Aditya Gupta
718 Points
							
Obviously a and b are roots of the equation
x^2-5x+3=0
Now a+b=5 and ab=3
Also, a/b+b/a= (a^2+b^2)/ab= (a+b)^2/ab - 2= 25/3-2= 19/3 and a/b*b/a= 1.
So equation whose roots are a/b and b/a is
x^2-19x/3+1=0
Or 3x^2-19x+3=0
20 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 170 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details