Grade 11Differential Calculus
I attached an image, l can`t solve that limit. Please sir help me to solve the question.
1 Answer
Arnab Saha
Approved Tutor Answer9 Years agoTake (n+1)! common from both numerator and denominator and cancel it out. You`ll be left with (n+3)/n. Express it as 1+(3/n). Now as n tends to infinity, 3/n tends to 0. Therefore you`re left with just 1 which is the limit. If you have further queries please ask.
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