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I applied L-Hospital’s rule and got a ifferent answer which is not in the options. MY answer={(2a*alpha+b^2 }/2;

I applied L-Hospital’s rule and got a ifferent answer which is not in the options.
 
MY answer={(2a*alpha+b^2 }/2;

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Grade:12th pass

1 Answers

Vikas TU
14149 Points
one year ago
Dear student 
You have applies lhospital wrongly , 
It will be – sin( ax^2 + bx + c) *(2ax +b) / ( 2x – 2a) 
apply differentiation again.
{(2a) (-sin(ax^2 + bx + c) -cos(ax^2 + bx +c) (2ax +b)^2 } / 2 
Now put value of a. 
Good Luck 
 

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