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Differentiate each side wrt x we get
cosy dy/dx = cos (a+y) - xsin(a+y) dy/dx
Replace x from original equation, rearrange dy/dx,
dy/dx (cosy + sin(a+y) siny/cos(a+y)) = cos(a+y)
Multiply both sides by cos(a+y)
dy/dx (cosycos(a+y) +sinysin(a+y)) =(cos(a+y))^2
dy/dx(cos(a+y-y)) =(cos(a+y)) ^2
So, dy/dx = cos^2(a+y)/cosa
Hence proved
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