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How to find the derivative of y=cosec( tan √x )? (By normal method as well as first-principle method)

How to find the derivative of y=cosec( tan √x )?
(By normal method as well as first-principle method)

Grade:12

2 Answers

Arun
25750 Points
4 years ago
Dear student
 
dy/dx = – cosec (tan √x) cot (tan √x) sec2 (tan √x) * ½ x3/2
 
Hope it helps
In case of nay difficulty, please feel free to ask again.
Aditya Gupta
2081 Points
4 years ago
dear abdul, aruns ans is wrong. correct answer is:
dy/dx = – cosec (tan √x) cot (tan √x) sec2(√x) *(1/2) x – ½
this can simply be calculated by using chain rule:
d(cosec(tan √x))/d(tan√x) * d(tan√x)/d(√x) * d(√x)/dx
kindly approve :))

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