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How to evaluate this... i know its simple but am stuck..

ananya bhat , 7 Years ago
Grade 11
anser 1 Answers
Aditya Gupta
write limit as 
Lt log(1+x^3)/x^3 * Lt (x/sinx)^3
now obviously  Lt (x/sinx)^3=1^3 = 1
for Lt log(1+x^3)/x^3 , put y=x^3
so Lt log(1+y)/y
now use l hospital rule we get
Lt 1/(1+y) = 1
so answer is 1
Last Activity: 7 Years ago
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