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Grade: 11
        
How to evaluate this... i know its simple but am stuck.. 
one year ago

Answers : (1)

Aditya Gupta
1720 Points
							
write limit as 
Lt log(1+x^3)/x^3 * Lt (x/sinx)^3
now obviously  Lt (x/sinx)^3=1^3 = 1
for Lt log(1+x^3)/x^3 , put y=x^3
so Lt log(1+y)/y
now use l hospital rule we get
Lt 1/(1+y) = 1
so answer is 1
one year ago
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