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How function f(x) = (tan x) – x is an always increasing function?

Siddharth verma , 11 Years ago
Grade 12
anser 1 Answers
Jitender Singh
Ans:
f(x) = tanx - x
f^{'}(x) = sec^{2}x - 1 = tan^{2}x\geq 0
So, f(x) is always increasing.
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty
Last Activity: 11 Years ago
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