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How function f(x) = (tan x) – x is always increasing function?

Siddharth verma , 10 Years ago
Grade 12
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
f(x) = tanx - x
f^{'}(x) = sec^{2}x - 1 = tan^{2}x \geq 0
So thats why f(x) is always increasing.
Thanks & Regards
Jitender Singh
IIT Delhi
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