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Hope you remember playing with the soap bubble. The surface area and the volume increase with the increase in bubble size. At an instance, the bubble diameter is 10 mm and is observed to grow. What is the change in surface area with change in volume, when bubble diameter is 10 mm

Harish bhavirisetty , 4 Years ago
Grade 12th pass
anser 1 Answers
Askiitians Tutor Team

When we think about soap bubbles, it's fascinating to see how their surface area and volume change as they grow. To understand the relationship between the change in surface area and the change in volume, we can use some geometry. Let’s break it down step by step.

Understanding the Geometry of a Bubble

A soap bubble is essentially a sphere. The formulas we need to know are:

  • Surface Area (A) of a sphere: A = 4πr²
  • Volume (V) of a sphere: V = (4/3)πr³

Here, r is the radius of the bubble. Since the diameter of the bubble is given as 10 mm, we can find the radius:

Radius (r) = Diameter / 2 = 10 mm / 2 = 5 mm

Calculating Initial Surface Area and Volume

Now, let’s calculate the initial surface area and volume of the bubble:

Surface Area (A):

A = 4π(5 mm)² = 4π(25 mm²) = 100π mm²

Volume (V):

V = (4/3)π(5 mm)³ = (4/3)π(125 mm³) = (500/3)π mm³

Finding the Change in Surface Area with Change in Volume

To find the relationship between the change in surface area and the change in volume, we can use calculus. Specifically, we can find the derivatives of the surface area and volume with respect to the radius.

Derivatives of Surface Area and Volume

Taking the derivative of the surface area with respect to the radius:

dA/dr = 8πr

Taking the derivative of the volume with respect to the radius:

dV/dr = 4πr²

Finding the Ratio of Changes

Now, we can find the ratio of the change in surface area to the change in volume:

Using the chain rule, we have:

dA/dV = (dA/dr) / (dV/dr) = (8πr) / (4πr²) = 2/r

At the moment when the radius is 5 mm:

dA/dV = 2/5 mm = 0.4 mm⁻¹

Interpreting the Result

This means that for every unit increase in volume, the surface area increases by 0.4 units at the moment when the bubble's diameter is 10 mm. This relationship highlights how the surface area grows at a different rate compared to the volume as the bubble expands.

In summary, as the soap bubble grows, the surface area increases at a rate of 0.4 mm⁻¹ relative to the volume when the diameter is 10 mm. This interplay between surface area and volume is a beautiful aspect of geometry and physics, illustrating how shapes behave in three-dimensional space.

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