Differential Calculus> Hi, Please answer with proper steps: Repl...

Hi,
Please answer with proper steps:
Reply as soon as possible.

Kush Raval , 6 Years ago

Grade 11

1 Answers

Pintu Chaudhary

We know that the function is continuous at x=c only when the functional value is equal to limiting value. i.e,

$\lim_{x\rightarrow c}=f(c)$

so, $(\lim_{x\rightarrow 0})$ $\frac{x}{1-\sqrt{1-x}}$ = f(0)

and

$(\lim_{x\rightarrow 0})$ $\frac{x}{1-\sqrt{1-x}}$

= $(\lim_{x\rightarrow 0})$ $\frac{x}{1-\sqrt{1-x}}$ $\tfrac{1+\sqrt{1-x}}{1+\sqrt{1-x}}$

= $(\lim_{x\rightarrow 0})$ $\tfrac{x(1+\sqrt{1-x})}{1-1+x}$

= $(\lim_{x\rightarrow 0})$ $1+\sqrt{1-x}$

=1+1=2

,therefore f(0)=2 Ans.

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Differential Calculus> Hi, Please answer with proper steps: Repl...

Hi,Please answer with proper steps:Reply as soon as possible.

Kush Raval , 6 Years ago

Pintu Chaudhary

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Hi,
Please answer with proper steps:
Reply as soon as possible.

Find dy/DX when y=x^sinx+sin-1√x.

Please give me the solution of this problem.

Example 20. (i) In a AABC, find the maxima and minima of u = sin A sin B sin C
where A + B + C = T
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