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Differential Calculus> help please............

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help please.........

milind , 11 Years ago

Grade 12

1 Answers

Y RAJYALAKSHMI

Let f(x) is define over the interval [0, a], then the odd extenstion of f(x) over the interval [-a, a] is defined as

f(x) = – f(–x); –a

= f(x); 0

For the given function f(x) = x² + x + sinx – cosx + log(1 + |x|) over the interval [0, 1], the odd extension on the interval [–1, 1] is

– [(– x)² + (– x) + sin(– x) – cos(– x) + log(1 + |x|)]; for –1

= – [x² – x – sinx – cos x + log(1 + |x|)]

= – x² + x + sinx + cos x – log(1 + |x|)]

Last Activity: 11 Years ago

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