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Help …....image attached

milind , 10 Years ago

Grade 12

1 Answers

Jitender Singh

Last Activity: 10 Years ago

Hello student,
Please find answer to your question
$ycos(x) + xcos(y) = \pi$
$y(0)cos(0) + 0.cos(y(0)) = \pi$
$y(0)= \pi$
Differentiate
$y'cos(x) - ysin(x) + cos(y) - xsin(y)y' = 0$
$y'(0)cos(0) - y(0)sin(0) + cos(y(0)) - 0.sin(y(0))y'(0) = 0$
$y'(0) + cos(\pi ) = 0$
$y'(0) = 1$
$y'(cos(x) - xsin(y)) = ysin(x) - cos(y)$
Differentiate
$y''(cos(x) - xsin(y))+y'(-sin(x)-sin(y)-xcos(y)y') = y'sin(x)+ycos(x) - sin(y)y'$ $y''(0)(cos(0) - 0.sin(y(0)))+y'(0)(-sin(0)-sin(y(0))-0.cos(y(0))y'(0)) = y'(0)sin(0)+y(0)cos(0) - sin(y(0))y'(0)$ $y''(0) = y(0)$
$y''(0) = \pi$

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