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Grade 12Differential Calculus

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Profile image of milind
11 Years agoGrade 12
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1 Answer

Profile image of Nishant Vora
11 Years ago
Hi student,

The limt of question provided by you exist and it is 0(finite)

So there has to one of the many inderminant forms now denomenatr goes to zero.

So the numerator sud also go to zero

So f(x)=\pm3

but -3 is nt in option so +3