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Find the value of the following limit- lim-(x-? p/2)??tan2x/(x-p/2)?

vardhan , 11 Years ago
Grade 12
anser 1 Answers
Rinkoo Gupta
lim x->pi/2 tan2x/(x-pi/2)
on putting values we get tan(pi)/(pi-pi)=0/0
so by sing L'Hospital rule,we get
limx->pi/2 2sec2(2x)/1
=2sec2(pi)=2(-1)2=2 Ans.
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
Last Activity: 11 Years ago
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