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Find the value of the following limit- lim-(x-? p/2)??tan2x/(x-p/2)?
lim x->pi/2 tan2x/(x-pi/2)on putting values we get tan(pi)/(pi-pi)=0/0so by sing L'Hospital rule,we getlimx->pi/2 2sec2(2x)/1=2sec2(pi)=2(-1)2=2 Ans.Thanks & RegardsRinkoo GuptaAskIITians Faculty
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