Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the value dy/dx if y=1+ sinx - cosx ÷1+ sinx + cosx

Find the value dy/dx if y=1+ sinx - cosx ÷1+ sinx + cosx

Grade:12

2 Answers

Ananya
34 Points
3 years ago
Y=1+sinx-cosx+sinx+cosxY=1+2sinxtaking log on both sides logy=log1+log2sinx1/y.dy/dx=1/2sinx.2cosxdy/dx=y(cotx)dy/dx=[1+2sinx]cotx
urvashi verma
26 Points
3 years ago
firstly,try to make y in a simpler form by using formulas as [1-cosx = 2(sin2x/2) ],[ 1+cosx =2(cos2x/2) ] and sinx = 2 sin(x/2) .cos(x/2).after putting these in your question and taking 2sin(x/2) common from numerator and 2 cos(x/2) from denominator your Y will reduced to tan (x/2) and thus its derivative is given by sec2(x/2) / 2.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free