Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

find the point on the curve y^2=4x which is nearest to the point (2,-8)

find the point on the curve y^2=4x which is nearest to the point (2,-8)

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Let (t^2,2t) is a point in given curve which is nearest from (2,-8)
S=distance between given points =root {(t^2-2)^2+(2t+8)^2}
S^2=(t^2-2)^2+(2t+8)^2
differentiate w.r.t t 
2sds/dt=2 (t^2-2) 2t +2 (2t+8)2
ds/dt=0
t^3-2t+2t+8=0
t=-2 
hence unknown point is (4,-4)
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free